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Consider y = x² which has its vertex at (0, 0) y = (x 6)² is a translation 6 units to the left so the vertex moves to (6, 0) y = 3(x 6)² is a stretch (squeeze) parallel to the x axis which does not affect points on the x axis so the vertex stays at (6, 0)Vertex\(y3)^2=8(x5) vertex\(x3)^2=(y1) parabolavertexcalculator vertex y=2x^{2}4x12 en Related Symbolab blog posts Practice, practice, practice Math can be an intimidating subject Each new topic we learn has symbols and problems we have never seen The unknowingFind the Vertex Form y=x^23 Complete the square for Tap for more steps Use the form , to find the values of , , and Consider the vertex form of a parabola Substitute the values of and into the formula Cancel the common factor of and Tap for more steps Factor out of

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Y=x^2-4x 3 vertex

Y=x^2-4x 3 vertex- Write the quadratic function given in vertex forms y= 3(x2) ^2 5 in standard form asked in ALGEBRA 2 by anonymous standardformofanequationWrite an equation in vertex form m = a (x – h)^2 K Now, expand the square formula m = a (x^2 y^2 2hx) K Multiply the inner side or bracket a x^2 a y^2 2

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Get stepbystep solutions from expert tutors as fast as 1530 minutes Your first 5 questions are on us!Hi the vertex form of a parabola, where(h,k) is the vertexY=x^24x3 in vertex form Y=x^24x3 in vertex form How to solve for vertex form y = x^2 4x – 1 Answers 2 Get Other questions on the subject Mathematics Mathematics, 1330, mbatton879 In the coordinate plan (6,9) b (3,9) c (3,3) def is shown in the coordinate plan below Answers 1 continue Rewrite in \(y=a(x−h)^{2}k\) form and determine the

 View Chapter 2 Project Pre Calculusdocx from MAC 1140 at Florida International University Yousef El Hajj Chapter 2 Project 1 identify the vertex and intercepts of the graph of y=x^24x3 A) TheA free online vertex form calculator can convert vertex form to the standard form of a parabola If you want to know how to change the vertex to standard form, let's start!The Distance Between The Vertex Of The Parabola Y X 2 4x 3 And The Centre Of The Circle The distance between the vertex of the parabola y = x 2 4x 3 and the centre of the circle x 2 = 9 (y 3) 2 is 1) 2√3 units 2) 3√2 units 3) 2√2 units 4) √2 units 5) 2√5 units

 Complete the square to write y = 3x2 12x 7 in vertex form, y = a(x h)2 k y = 3(x2 4x) 7 y = 3(x2 4x 4) 7 Vertex is (2,4) Step 1 Complete the square y = − x2 − 4x = −(x − 2)2 −4 Step 2 Arrange so that you get the form (x −xv)2 = 4a(y − yv) y = − (x −2)2 −4 = −(x −2)2 4 ⇒ (x − 2)2 = 4 − y ⇒ (x − 2)2 = −(y − 4) From here you can conclude that the vertex is at (2 `y=2(0)^24(0)3=3` So the yintercept is (0,3) To find the xintercepts, you plug in y=0 and solve for x This is a little harder `0=2x^24x3` There are two ways to solve something like this

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Get an answer for 'graph y=3/4x^2 plot the vertex and four additional points, two on each side of the vertex' and find homework help for other Math questions at eNotesGiven {eq}y = 2x^2 4x 3 {/eq}; vertex = (1, 1 ) Stepbystep explanation Given the equation of a parabola in standard form f(x) = ax² bx c ( a ≠ 0 ) Then the x coordinate of the vertex is x = f(x) = 2x² 4x 3 ← is in standard form with a = 2 and b = 4 , then = = 1 Substitute x = 1 into f(x) for corresponding y coordinate of vertex

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All equations of the form a x 2 b x c = 0 can be solved using the quadratic formula 2 a − b ± b 2 − 4 a c The quadratic formula gives two solutions, one when ± is addition and one when it is subtraction x^ {2}4xy5=0 x 2 4 x − y − 5 = 0 This equation is in standard form ax^ {2}bxc=0 Substitute 1 for a, 4 for b, andFind the Vertex y=2x^24x3 y = 2x2 − 4x − 3 y = 2 x 2 4 x 3 Rewrite the equation in vertex form Tap for more steps Complete the square for 2 x 2 − 4 x − 3 2 x 2 4 x 3 Tap for more steps Use the form a x 2 b x c a x 2 b x c, to find the values of a a, b b, and c c a = 2, b = − 4, c = − 3 a = 2, b = 4, cGiven a parabola whose equation is {eq}y=x^24x3 {/eq} Then we have that {eq}a=1, b=4, c=3 {/eq} To graph the parabola we first have to find its characteristic points

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Algebra Graph y=2x^24x3 y = 2x2 4x − 3 y = 2 x 2 4 x 3 Find the properties of the given parabola Tap for more steps Rewrite the equation in vertex form Tap for more steps Complete the square for 2 x 2 4 x − 3 2 x 2 4 x 3 To find corresponding value of ycoord of vertex , substitute x = 2 into the function x = 2 y = −(2)2 4(2) −3 = − 4 8 − 3 = 1 ⇒ vertex = ∣∣ ∣ ∣¯¯¯¯¯¯¯¯¯¯¯¯¯¯a a 2,1 a a ∣∣ −−−−−−− − Here is the graph of y#= x^24x3 graph {x^24x3 10, 10, 5, 5} Answer linkGiven the equation y = 3x^2 x 3 To find the vertex of a parabola 1 Establish the values for a, b, and c in the given equation a = 3, b = 1, c = 3

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🔴 Answer 2 🔴 on a question 3 Write y = x2 4x 6 in vertex form A y = (x 2)2 2 B y = (x 2)2 2 C y = (x 2)2 4 D y = (x 2)2 4 the answers to ihomeworkhelperscomAnswer (1 of 3) There's no need to use graping software not that there's anything wrong with that, except that it doesn't really give any insight you can complete the square notice that y^2 2y is very similar to y^2 2y 1 = (y1)^2 So y^2 2y = (y1)^2 1 which means y^2 4xThe vertex is at (p,q)=(2,1) You can find the y=intercept by setting x=0 and solving for y It's easiest to do this with the general form y=x^24x3 y = 0)3 y=3 The yintercept is y=3 To find the xintercepts, factor, set y=0 and solve for x You have to solve by factoring y=x^24x3 0 = x^24x3 0 = (x3)(x1) Which means that the x

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 Answer y = x² 4x 12 When y = 0 x² 4x 12 = 0 x² 4x 12 = 0 (x 2)(x 6) = 0 x = 2 or x = 6 The xintercepts are 2 and 6 y = (x² 4x) 12 yCorrect answer to the question 3 Write y = x2 4x 6 in vertex form A y = (x 2)2 2 B y = (x 2)2 2 C y = (x 2)2 4 D y = (x 2)2 4Find the Vertex Form y=x^24x3 Complete the square for Tap for more steps Use the form , to find the values of , , and Consider the vertex form of a parabola Substitute the values of and into the formula Simplify the right side Tap for more steps Cancel the common factor of and

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Given the parabola with standard equation {eq}y=\dfrac{3}{4}x^2 {/eq} Then we have that {eq}h=k=0, a=\dfrac{3}{4} {/eq}, so the vertex is the point {eq}V(0,0) {/eq}Answers The general equation of a quadratic is expressed as y = ax^2bxc To convert the general equation to vertex form, we need to obtain this form (y k)= a (x h)^2 This could be done by using completing the square method y = –3x^2 – 12x – 2 y 2 = –3 (x^2 4x)Janine da Silva The graph of the quadratic function f (x) = 3 4 x – x 2 intersects the yaxis at point A and has its vertex at point B (a) Find the coordinates of B (3 A quadratic function, f (x) = ax 2 bx, is represented by the mapping diagram below

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Qudratic y = x2 4x — 3 to vertex form Step 1 Find the value of b then divide it by two, First find the value of "b " b = 4 Then, divide b by two Step 2 Square it or (—)2 (2)2 = Step 3 Add and subtract that value Now that the trinomial is a perfect square, write itQuestion Rewrite the equation y=–2x^24x3 in vertex form Identify the vertex and the axis of symmetry Answer by ewatrrr(243) (Show Source) You can put this solution on YOUR website! Convert to vertex form ( y = a (x b)^2 c where (b, c) is the vertex ) y = x^2 4x y = (x 2)^2 4 so the vertex is at ( 2, 4) answer

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 The equation of a parabola in vertex form is y = a(x h)² k where (h, k) are the coordinates of the vertex and a is a multiplier To obtain this form use the method of completing the square add/ subtract (half the coefficient of the x term )² y = x² 4x (2)² (2)² 11 = x² 4x 4 4 11 = (x 2)² 7 ← in vertex form4 x 2 8 x 8 = y Subtract y from both sides Subtract y from both sides 4x^ {2}8x8y=0 4 x 2 8 x 8 − y = 0 This equation is in standard form ax^ {2}bxc=0 Substitute 4 for a, 8 for b, and 8y for c in the quadratic formula, \frac {b±\sqrt {b^ {2}4ac}} {2a}Find the Vertex y=x^24x3 Rewrite the equation in vertex form Tap for more steps Complete the square for Tap for more steps Use the form , to find the values of , , and Consider the vertex form of a parabola Substitute the values of and into the formula Find the vertex

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Sketch the graph, find the vertex, the focus, and the directrix Parabola The conic with the value of eccentricity standing as unity is the curve called theWe are given the function {eq}y=5x^24x3 {/eq} We want to know the vertex of the given function So, we have Solution The graph of the givenAnswer (1 of 4) The coordinates of the vertex are (2,1) Solution The function is a quadratic function that is written in standard form, ax^2 bx c = 0, a not 0 Rewrite the function in vertex form, a(x h)^2 k, a not 0 by completing the square on the original function The coordinates

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F(x)= x^24x3 to find the vertex, use (b/2a) 4/2(1) = 4/2 = 2 This is the x part of the vertex (2,?), then we use 2 in place of x in f(x) f(2) = (2)^24(2)3 = 4 = 1 Therefore the vertex is (2,1) To find the x intercepts, you set the equation to equal 0 x^24x3=0 (does it factor?) (x3)=0, (x1)=0 x= 3, x=1 To find the yAnswer Vertex form of quadratic equation is => Y = a(X h)^2 k Let's simplify the given equation Add and subtract coefficient of X^2 on left side Y = 4X^2 8X 4 4 3 => Y = 4(X^2 2X 1) 4 3 => Y = 4(X 1)^2 1 So vertex of this parabola is V = (1,1)Correct answers 3 question Write y = x2 − 4x − 1 in vertex form y = (x 2)2 − 5 y = (x 2)2 5 y = (x − 2)2 − 5 y = (x − 2)2 5

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Vertex f (x)=y=x^24x \square!Functionvertexcalculator vertex f(x)=x^{2} en Related Symbolab blog posts Functions A function basically relates an input to an output, there's an input, aGiven y= 8x^2 4x 3 We need to find the vertex We know that a= 8 b= 4 c = 3 Let V be the vertex such that V (xv, yv) xv = b/ 2a ==> 4/2*8 = 4/16 = 1/4

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Transcribed image text Question 14 of 50 Find the coordinate of the vertex of the parabola y = x^2 4x 1 by making use of maxima and minima since the vertex of the parabola could be the minimum or maximum point Select the correct response (2,3) (21) (12) (3,2) Question 22 of 50 What is the area bounded by the curve y = 6 cos x and the xaxis from x pi/6 to x = pi/2?Algebra > Trigonometrybasics> SOLUTION how do you identify the vertex, focus, and directrix of the parabola y=x^24x3 And graph it Log On Algebra Trigonometry SectionAlgebra > Graphs> SOLUTION graph f(x)=x^24x3, labeling the yintercept, vertex, and axis of symmetry please help Log On Algebra Graphs, graphing equations and inequalities Section

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View this answer The given equation is y =x24x−3 y = x 2 4 x − 3 To convert this into the vertex form, we have to complete the squares Adding 3 3 on both sides

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